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how do i solve this exponential equation... e^2x-4(e^x)=0
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e^(2x)-4(e^x)=0
Let z = e^x, so z^2 = e^(2x) So your goal is to solve z^2 - 4z = 0 Then use the solutions in terms of 'z' to find the solutions in terms of 'x'
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oh sorry, i understood :) thanks
That's great. What did you get for the answers?
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i got x = ln4
very nice, I'm getting that as well
awesome
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