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15x+15 ------- x^2-1
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Factor out the 15 giving you: 15(x+1) Factor x^2 -1 into: (x-1)(x+1) You should end up with: 15/(x-1)
Are there any common factors you can take out?
\[\frac{15x+15}{x^2-1}=\frac{15(x+1)}{(x-1)(x+1)}\]Can you cancel the common factor in the denominator and numerator?
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