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Solve: 8^x-1 = 2^x+1
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Do you have n idea how to start on this problem?
hint: 8 = 2^3
no i have no clue
\[\large 8^{x-1} = 2^{x+1} \implies (2^3)^{x-1} = 2^{x+1}\]
it wants me to solve for x though
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Since you have the same base (2) on both sides you can remove it, so you end up with 3(x+1) = x + 1, Now you can solve for x
3(x-1), not 3(x+1) - it was a typo
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