Question

Is the domain of f(x)=3sqrt(x-64)+5 {xIx>=4}?

Answer 1

@jim_thompson5910

Answer 2

You're close

Answer 3

x>=64

Answer 4

oh wait, is it \[\Large f(x) = \sqrt[3]{x-64}+5\] ?

Answer 5

Yes =)

Answer 6

so it's real

Answer 7

The domain of any cube root function is the set of all real numbers. This is not the same as a square root.

This is because you can take the cube root of any negative number

Answer 8

I see! =) so it should be all real numbers?

Answer 9

yes

Answer 10

Thank you!

Answer 11

yw