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Mathematics 23 Online
OpenStudy (anonymous):

The figure shows a pattern of a regular hexagon and equilateral triangles. A regular hexagon surrounded by 6 equilateral triangles on all 6 sides is shown. An interior angle of the hexagon is marked as x. Which of the following describes the correct method to find the measure of angle y? The exterior angle of the hexagon is the angle of the equilateral triangle. y = 60°. The exterior angle of the hexagon is the interior angle of the equilateral triangle. y = 180° – 60°. The exterior angle of the hexagon is the exterior angle of the equilateral triangle. y = 180° – 120°. The i

OpenStudy (anonymous):

OpenStudy (anonymous):

The interior angle of the equilateral triangle and y are supplementary angles. y = 90° - 60°. thats the last option

OpenStudy (anonymous):

@Ishaan94

OpenStudy (anonymous):

@lgbasallote

OpenStudy (lgbasallote):

how did you go on deciding who to tag? i mean @Hero has higher score than me...

OpenStudy (anonymous):

cause youve helped me before and yeah he does but ive never really spoken to him ever

hero (hero):

@lgbasallote, you don't have to defer to me, I'm positive you can help with this question.

OpenStudy (lgbasallote):

i dont like this kind of geometry though =_=

OpenStudy (lgbasallote):

sorry

OpenStudy (anonymous):

and theres another one that i have been extremely stuck in i dont understand

OpenStudy (anonymous):

and its okay thanks though!

hero (hero):

Wow really @lgbasallote ?

hero (hero):

|dw:1338533571025:dw|

hero (hero):

To find exterior angle, do 360/6 = 60, then 180 - 60 = 120

OpenStudy (anonymous):

oh i see now thank you (:

OpenStudy (anonymous):

Salma photocopied the design for a monorail track system. The figure below shows the design and its photocopy. Two irregular quadrilaterals ABCD and EFGH are drawn. EFGH is the photocopy of design ABCD. AB measures 15 meters, DC measures 17 meters. No dimensions are shown on EFGH. The ratio of DA : BC is 1 : 2. The total length of track on the design is 47 meters. What is the length, in meters, of side EH on the photocopied image?

OpenStudy (anonymous):

thats the other one i did not understand at all

hero (hero):

This has that online test feel to it

OpenStudy (anonymous):

it really is the most annoying kind -.- i have to take this last test in order to graduate tomorrow

hero (hero):

Hold on a sec. I will show you

OpenStudy (anonymous):

okaay

hero (hero):

OpenStudy (anonymous):

i saw where i went wrong with my calculations thanks sooo much!

OpenStudy (anonymous):

i am assuming the length of the photocopied image is the same?

hero (hero):

You don't have any choice but to assume

OpenStudy (anonymous):

i guess lol i figured

hero (hero):

I'm looking back at that first question. I realize it wants us to find the measure of angle y

hero (hero):

Angle y is the interior of the regular hexagon, so by default, it is 120

hero (hero):

I hope it isn't too late to change your answer for that one

OpenStudy (anonymous):

The exterior angle of the hexagon is the interior angle of the equilateral triangle. y = 180° – 60°. would this be the answer since it equals to 120 and no not at all (:

hero (hero):

actually no. That has nothing to do with it. Angle y has nothing to do with exterior of hexagon or interior of equilateral triangle. Look at the picture again.

hero (hero):

Now that I look at it, we know that angle y is obtuse so it has to be greater than 90. None of the options make sense, so you have no choice but to pick the one that gives 120

hero (hero):

So pick the one that equals 120. If it is wrong, then it is a shame because the interior of the hexagon is 120 degrees and that is the angle that y corresponds to.

OpenStudy (anonymous):

yeah i got 120 also so i dont know which one would be correct

hero (hero):

Just pick the one you wanted to. The 180 - 60 = 120 option. It doesn't make sense but it is the closest to correct.

OpenStudy (anonymous):

okay thank you so much would i be able to ask you if i need more help?

hero (hero):

You can just ask the question and anyone who is available to help will help. I'm not always on here.

OpenStudy (anonymous):

oh i know that i was just saying for right now if i can tag you or something if i need anything unless your logging out now then thats useless lol

hero (hero):

You can tagg me, but no guarantees

OpenStudy (anonymous):

okaay thats good enough for mee thank you !

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