Question

Lim (x^2-x+6)/(x-2) when x goes to 2.
How to solve it?

Answer 1

factorise first

Answer 2

But the equation of the numeiator has complex roots.

Answer 3

what is the answer? is it equal to 3?

Answer 4

No, the answer is that the lim not exist. But how I found this solution?

Answer 5

just assign the value of x in the limit..

Answer 6

\[\lim_{x \rightarrow 2} (2^2-2+6)/(2-2)\]

Answer 7

\[= \lim_{x \rightarrow 2} 8/0 = \infty \]

Answer 8

But the 0 on the denominator proof that has no limit?

Answer 9

Aha right

Answer 10

yep..the limit is does not exists when it is equal to infinity

Answer 11

Males sense. Thanks!

Answer 12

For your information, any number divided by 0 is equal to infinity. So, there is no limit. Tq