Question

Which of the following is the factored form of the given equation?

6x^2 + 2x - 8 = 0

Answer 1

2(3x + 4)(x - 1) = 0
(6x + 1)(x - 8) = 0
2(3x + 4)(x + 1) = 0

Answer 2

= 2(3x^2+x-4)
=2(3x+4)(x-1)

Answer 3

ok explain please

Answer 4

ok so its the first one

Answer 5

you can find it by expand each of the equation..then you will get only the 1st equation can form the given equation.

2(3x + 4)(x - 1) = 0
(6x+8)(2x-2)=0
12x^2 +4x - 16 = 0
2(6x^2 + 2x -8) = 0

Answer 6

then you can expand the 2nd and 3rd, but you will not get the same as the equation given.

Answer 7

so, the answer is 2(3x + 4)(x - 1) = 0

Answer 8

The 2 need only be expanded in the (3x+4) putting it in both terms result in it being expanded twice.

Answer 9

ok thanks guys

Answer 10

It would be much clear if you expanded the second two terms getting 2(3x^2+x-4) then expand the with the 2 getting 6x^2 + 2x -8