Help needed quickly..thanks :)

Question

anonymous · Answer

attachment

anonymous · Answer

@saifoo.khan @ash2326

saifoo.khan · Answer

i did a similar question before! D:

anonymous · Answer

oh gce olevel then..hi5 bro:D

saifoo.khan · Answer

How did you know? D:
are u doing Olevels? where?

anonymous · Answer

srilanka...:)

saifoo.khan · Answer

My neighbor! :D
im doing A-levels. :D

anonymous · Answer

oh :) ur from?

saifoo.khan · Answer

Pakistan.

anonymous · Answer

oh good..and ur o level result.?..must be like very high :D ...hehe

saifoo.khan · Answer

i got a A in maths.
it's easy man.
are u giving maths this year? Maths paper is on 6th june.

anonymous · Answer

exactly bro, i almost completed all past papers, then i jst came acrss this question, in one of my previous batch (MOCK) past paper, so just wnted to do it perfectly?

saifoo.khan · Answer

If you completed all papers then you did it perfectly. :D

anonymous · Answer

hehe, but still i cant prove the  first question...wait can we assume tht sides are equal and then build a similarity?

saifoo.khan · Answer

to be honest even i was unable to do this question! lol.

saifoo.khan · Answer

Well, yes let's assume sides.

anonymous · Answer

so BC=BE and...is it enough for 2 marks?

saifoo.khan · Answer

There's a question, N04_paper 2 question 4.
it's same as this.

anonymous · Answer

isnt it a bit different from this, hm...? so what do u think the answer is ? i mean for this question

saifoo.khan · Answer

Hold on a sec.

anonymous · Answer

take ur time:)

saifoo.khan · Answer

i asked my friends.. they gave me this:

a)  SAS (side angle side)
because AB ~ FB and BC ~ BE
They can't solve more..

anonymous · Answer

how can AB~FB?

anonymous · Answer

we didnt still come to that

anonymous · Answer

okay what about this, since it is a rectangle angle  BAC= angle BFE

anonymous · Answer

90 degrees

anonymous · Answer

we have two info to prove it...am i correct?

anonymous · Answer

@emcrazy14. what du think

anonymous · Answer

This is a tricky question. I'm THINKING.... xP

anonymous · Answer

I hate these geometrical proof questions. O_O

anonymous · Answer

same here..:D hi5

anonymous · Answer

HAHA! I'm still trying but not even close to getting a solution. O.o And CIE has begun to include so many of these in recent exams. I wonder how I'm going to do it if it comes in the paper? :(

anonymous · Answer

i mean, check if my answer is correct....

anonymous · Answer

Where?

anonymous · Answer

i just wnted to justify it with u...

anonymous · Answer

check it now okay

anonymous · Answer

prove similarity between 
ABC = FBE
BC = BE ( shown that is is a square= equal sides)
angle BAC = angle BFE {90 degrees since it is a rectangle)

isnt it enough for similarity?

anonymous · Answer

I am not sure. You have to prove at least three things, either AAS, SAS,SSS.

anonymous · Answer

thats for congruency . for similarity they give only two things..coz in many of the mrking schemes they give 2 marks plus for two points

anonymous · Answer

You know if the question didn't say that ABFG was a rectangle, we could apply the RHS property to prove the congruence.

anonymous · Answer

Oh, sorry! But still for similarity, you either prove that the ratios of three sides is equal or the corresponding angles are equal.

anonymous · Answer

but isnt it the only choice to prove this? what do u think u have any solutions
?

anonymous · Answer

maybe for part b) RHS rule can be applied, i dont get that rectangle part...if they dont tell it is rectangle how wil u know it is 90?

anonymous · Answer

Rectangle's angles are 90 degrees. But this question is really problematic. first, it says it is a rectangle and then it says prove that ABFG is a square. :o

anonymous · Answer

yes, so both square and rectangle has an angle of 90....hm...i think we have to ask some one else..who is good at this..

anonymous · Answer

Yeah. O.o

anonymous · Answer

@ash2326

anonymous · Answer

I just worked out something. It may be silly but here it is:

anonymous · Answer

ok

anonymous · Answer

e know ABFG is a rectangle. Therefore, angle ABF is 90 degrees. Similarly, BCDE is a square so we can conclude that angle CBE is 90 degrees. Now subtracting CBF from both ABF anf CBE leaves us with equal angles. ( angle CBF is common to both 90 degree angles)

anonymous · Answer

*We

anonymous · Answer

For part (b), we can use the AAS side property. Side CB =BE. Angle ABC=FBE and angle BAC=BFE. Hence, both are congruent.

ash2326 · Answer

Yeah @emcrazy141is right
Great work @emcrazy14

anonymous · Answer

Aww, thank you! It was simple. But we were all thinking it the hard way.