Help need please...quickly
A trader bought some paraffin for $500, he paid $x for each of litre of parrafin a) Find, in terms of x an expression for the numbers of litres he bought b) DUe to a leak, he lost 3 litres of paraffin. He sold the remainder of the paraffin for $1 per litre more than he paid for it. Write down an expression, in terms of x, for the sum of money he recieved?
@radar @shadowfiend @shivam_bhalla
@UnkleRhaukus @Ishaan94
I have to run an errand will be back in an hour.
ok
\[P(L)\times x($/L)=$500\]
okay first one i got it, its 500/x what about the next one
\[P(L-3)\times(x+1)($/L)\]
\[x+1(\frac{500}{x}-3)\]-----?
is this right @UnkleRhaukus
** \[(P-3)L\times(x+1)($/L)\] \[\left(\frac{500}{x}-3\right)L\times(x+1)($/L)\]
okay thanks, can u tell me how to multiply both (500....) and (x+1) showing steps very clearly...and if possible cn u suggest me a website to learn those.?
that would be a great help?
i think i have this right but im not sure because its a tricky problem\[\left(\frac{500}{x}-3\right)L\times(x+1)($/L)\]\[=\left(\frac{500}{x}-3\right)\times(x+1)$\]\[=500+\frac1x-3x-3\]
do u know any websites to learn this?
i mean expanding in fraction forms?
i dont off hand sorry
@saifoo.khan
my site is lagging. -_-
hmmm?i cn see it
I think "Uncle" pretty well expressed it. Here is my take on it. Here is what I know from what is given. 1. A trader purchased 500$ worth of paraffin in liter units. He paid x$ per liter. For part a) express in terms of x the number of liters purchased; No. of liters purchased is $500/$x. For b) To show the 3 liter loss the trader now has (($500/$x)-3) liters of paraffin. To show the price that he sold this per liter is: $(x+1) This is a $1 more per liter than he paid for it. To express the amount of money received from this sale we multiply the amoun in liters times the selling price per liter.: [($500/$x)-3][$(x+1)] Performing the arithmetical operations we get $500/$x (x$ + $1)-$3x-3 Now to the chalk board;|dw:1338582721150:dw|
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