Mathematics
14 Online
OpenStudy (anonymous):
17. y = x2 + 3x – 4
y = 2x + 2
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OpenStudy (anonymous):
what do u need to do with this problem?
OpenStudy (anonymous):
i dont know
OpenStudy (anonymous):
you have y = 2x + 2
plug that in for the initial equation then solve for x
OpenStudy (anonymous):
can you show me how
OpenStudy (anonymous):
2x + 2 = x2 + 3x - 4
x2 + 3x - 2x = 2 + 4
can you continue?
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OpenStudy (anonymous):
no what else do to do
OpenStudy (anonymous):
x^2 + x - 6 = 0
factor it out you have (x+3)(x-2) = 0
solve for x
then plug your answer in to find y
OpenStudy (anonymous):
what else do you do after this
OpenStudy (anonymous):
what are your answers for x?
OpenStudy (anonymous):
i don know hwo to do that
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OpenStudy (anonymous):
x + 3 = 0
x - 2 = 0
solve for that
OpenStudy (anonymous):
|dw:1338601263749:dw|
OpenStudy (anonymous):
yep. then plug that in the second equation to find y
OpenStudy (anonymous):
ok so the answer is 8
OpenStudy (anonymous):
@ninhi5 answer is 8 or 6
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OpenStudy (anonymous):
(–3, 6) and (2, –4)
(–3, –4) and (2, 6)
(–3, –4) and (–2, –2)
no solution
OpenStudy (anonymous):
pick one :)
OpenStudy (anonymous):
the 1st or 2nd
OpenStudy (anonymous):
nope nope
plug in -3 for y = 2x + 2 to solve for y => y = 2(-3) + 2 = ?
then do the same for -2
OpenStudy (anonymous):
-4 for the 1st then -2 for the second
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OpenStudy (anonymous):
IT IS THE THIRD
OpenStudy (anonymous):
Hooraaaayyyy! good job :)
OpenStudy (anonymous):
thankscan you help me with my other one