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Solve for c. 2abc + d = 3
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lol. subtract 'd' from both sides.
a,b,c,d are basically just terms. 2abc = 3 -d divide by '2ab' \[\frac{2abc}{2ab}=\frac{3-d}{2ab}\]
so what do you get now?
don't think what ab equals - the answer just be in terms of a,b,c, and d. that's it. \[\frac{\cancel{2ab}c}{\cancel{2ab}}=\frac{3-d}{2ab}\] this^ helps?
c=idk
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c = NOT 'idk' \[c=\frac{3-d}{2ab}\]
ok thank you
that's it!^ don't get afraid of the 'alphabets' - they are just a form of denotion, used in place of the numbers.
ok
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