Question

A doubt of factorization

Answer 1

\[11x ^{3}\left( x ^{3}-2y ^{2} \right)^{4} \times \left( 11y ^{5}\left( x ^{3}-2y ^{2} \right)^{2}+6x \left( x ^{3}-2y ^{2} \right)-12x ^{2}y \right)\]

Answer 2

I already did the first part, but now i am here...what should I do now?

Answer 3

dont answer it, just tell me which should be my next step

Answer 4

let x^3 - 2y^2 = t , say
then simplify
in the end you may substitute back t
that should make it bit easier.

Answer 5

\[11x ^{3}t ^{4}\times \left( 11y ^{5}t ^{2}+6xt-12x ^{2y} \right)\]

Answer 6

the last y is not an exponent...so now what should I do? I think I need 2 numbers that multiplied are -132 and added are 6..is that correct?

Answer 7

yep..thats what even i'd think..

Answer 8

did you get anyhting? coz i couldnt,,hmmn..

Answer 9

nope hehe...then i guess that this is the end of the problem