The monthly sales (in thousands of units) of a seasonal product are approximated by
S= 74.50 + 43.75 sin pi t/6
Where t is time in months, with t=1 corresponding to January. Determine the months when sales exceed 100,000 units

Question

The monthly sales (in thousands of units) of a seasonal product are approximated by
S= 74.50 + 43.75 sin pi t/6
Where t is time in months, with t=1 corresponding to January. Determine the months when sales exceed 100,000 units

anonymous · Answer

they really reach for these word problems don't they?

anonymous · Answer

Lol yeah. It's terrible.

anonymous · Answer

$$74.50+43.75\sin(\frac{\pi t}{6})>100$$
$$43.75\sin(\frac{\pi t}{6})>25.5$$
$$\sin(\frac{\pi t}{6})>.583$$ rounded. we can try various values for t since they all have too be integers

anonymous · Answer

okay thanks!

anonymous · Answer

1 doesn't work, because $\sin(\frac{\pi}{6})=.5$ but 2, 3 4 will work

anonymous · Answer

can visualize it here http://www.wolframalpha.com/input/?i=sin%28pi+t%2F6%29%3E.583+++from+1+to+12