Question

use the foil method (2x^5-6)(x^9-5)

Answer 1

Do you know how to use the foil method?

Answer 2

Wait

Answer 3

Me or him?

Answer 4

no

Answer 5

Okay so a way to remember how to use the foil method is first outer, inner last.

Answer 6

\(\begin{align}
\text{F.O.I.L. = First Outside Inside Last}\\
\hline \\
&(ax+b)(cx+d)\\ \ \\
\text{First:}&(\color{blue}{ax}+b)(\color{blue}{cx}+d)\to \color{blue}{ax}\cdot\color{blue}{cx}=\color{blue}{acx^2}\\
\text{Outside:}&(\color{green}{ax}+b)(cx+\color{green}{d})\to \color{green}{ax}\cdot\color{green}{d}=\color{green}{adx}\\
\text{Inside:}&(ax+\color{red}{b})(\color{red}{cx}+d)\to \color{red}{b}\cdot\color{red}{cx}=\color{red}{bcx}\\
\text{Last:}&(ax+\color{orange}{b})(cx+\color{orange}{d})\to \color{orange}{b}\cdot\color{orange}{d}=\color{orange}{bd}\\
\hline \\
(ax+b)(cx+d)&=\color{blue}{acx^2}+\color{green}{adx}+\color{red}{bcx}+\color{orange}{bd}
\end{align}\)

Answer 7

Get it?

Answer 8

i hate math lol

Answer 9

\[2x^14 - 6x^9 - 10x^5 + 30\]

Answer 10

That is two-x to the fourteenth power --- Minus six-x to the ninth, minus ten-x to the fifth, plus thirty.

Answer 11

thanks