Question

Someone please tell me how do I solve (x-k)(y-k)=?

Answer 1

the q is actually this
20x - 18<50< 36x - 16
20x - 18<50 eq1
36x - 16>50 eq2


solve individually
eq 1 for x and eq 2 for x then

1 5/6<x
3 2/5>x

is equivilent

Answer 2

you changed problem :P

Answer 3

Thanks :P

Answer 4

(x-k)(y-k)=0?
for k?

Answer 5

it just says (x-k)(y-k)=

Answer 6

they probably mean 0
so [k = x], [k = y]

Answer 7

okay supposly the answer is xy-xk-ky+k^2 but I have no idea how they got that

Answer 8

oh expansion :)

Answer 9

distributive proberty