Use the shell method to find the volume of the solid generated by revolving the region bounded by the curves and lines about the y-axis. y = 2x, y = (x/2), x = 1 I just need help setting it up, not necessarily the answer :)
|dw:1338751680973:dw| it will look something like this to find bounds plug in 1 for x in both equations .5 to 2 is your bounds :)
Oh yea, I found the bounds and transformed the euqations so that that they are x=2y and x=y/2
Sorry, shoulda mentioned that!
well shell method just means take rings big ring minuse litle ring (pif(x)^2)- (pi g(x)^2)
Oh really? I'm confused because in my book they are finding the height and circumference and thickness...?
well maybe they do it a different way but that is what it really is :P
Oh okay, I will try it like you suggested :)
|dw:1338752155936:dw|
shell method is not a "ring" method. but sometimes we have to use a similar process
y-axis. y = 2x, y = (x/2), x = 1 ; about the y-axis |dw:1338753604766:dw|
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