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Is the following statement true or false: If b^2-4ac<0 then there are two complex roots of the quadratic equation ax^2+bx+c=0
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And please state why the statement is true or false.
Do you know the Quadratic Formula? Consider how the Quadratic Formula is affected when \(b^2 - 4ac\) is negative: \[ x_1 = \frac{-b + \sqrt{\color{goldenrod}{b^2 - 4ac}}}{2a} \\ x_2 = \frac{-b - \sqrt{\color{goldenrod}{b^2 - 4ac}}}{2a} \\ \] If that part is negative, then won't you always get a negative under the square root?
Oh okay I was wondering how it fits in but now that you highlight it, it makes sense thank you!!! I understand
You're welcome. :)
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