Question

How do you find the domain and range of 1/(x+3)^2?

Answer 1

won't be all numbers except -3?

Answer 2

Yes @MSMR

Answer 3

why?

Answer 4

If x=-3, then you have 1/0

Answer 5

Yes you are right, when we put x=-3 we get 1/0, division by zero is undefined.

Answer 6

okay, so the domain makes sense - how do you find the range?

Answer 7

...hello?

Answer 8

The graph of \( y=\frac{1}{(x+3)^2} \) looks like this:

Answer 9

What do you think the range is?

Answer 10

the range is the set of all y points right? so everything greater than 0?

Answer 11

(0, infinity)?

Answer 12

Looks good to me.

Answer 13

Thank you! It makes sense to me now :)

Answer 14

Glad to help :)

Answer 15

Write \((x + 3)^{-2}\). As \(x\) gets closer to \(-3\), we see a vertical asymptote.