Question

refer to the function \[g(x)= 1+ \sqrt{x+3}\] . What is the range of g(x)

Answer 1

\[g(x)=1+\sqrt{x+3}\]

Answer 2

what's your question?

Answer 3

its at the top

Answer 4

you can use inverse functions and get the domain of the inverse if range gives you problems. The range would be all real numbers

Answer 5

x=> -3

1 to infinity right?

Answer 6

So get the inverse of the function= y= x^2-2x-2
and you know that the domain of the inverse function is equal to the range of the function