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Mathematics 13 Online
OpenStudy (anonymous):

what about listing the restrictions on the variable of: (3s+2)(2s-3)(2s+1)^2

OpenStudy (anonymous):

(4s+1)(s+1)

OpenStudy (anonymous):

could you show me the process please?

OpenStudy (anonymous):

sure.

OpenStudy (anonymous):

so basically what you need to do is make sure the first coefficient multiplies with factors of the last number in the equation, but the factors must add up to the middle number.

OpenStudy (anonymous):

uhh, thanks, but more of the factorization process? numbers please :)

OpenStudy (anonymous):

I just noticed, it's (2s+1)^2. So i'm gonna create a drawing. One sec.

OpenStudy (anonymous):

haha thanks! :D it's the number array isn't it?

OpenStudy (anonymous):

|dw:1338783901184:dw| I'm not sure what you mean by number array, but i could show u the process. the above drawing should come out to: 4s^2+2s+2s+1

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