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Is it possible to find the restricted number of (s) when you have (2s-3)(2s+1)
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Please show the process :D
(2s+1)(s-4) You know that 2s is on one side and s is on the other since s is a prime number. It has opposite signs because it is -minus- 7s.. then it is a guess and check process. which is not complex based on the fact that 4 can only be 1x4 and 2x2.
could you show the process for numbering though? I don't really get what you mean by prime numbering etc..
What do you mean by prime numbering? I am sorry, but there is really no 'process' that goes on when one factors...
okay nvm. forget it haha,
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