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x = 1/2 (y - 1)^2 + 8 Name the vertex.
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So (-1,8)?
\( \color{Black}{\Rightarrow x = a(x - h)^2 + k }\) (h,k) is the vertex :)
I didn't say -h,k
1 will be positive in the vertex. \((1,8)\)
What about for an equation like -2x^2 + 3?
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@lalaly :)
I didn't understand the equation...there isn't an equals sign :/
\( \color{Black}{\Rightarrow x = a(y - h)^2 + k }\) *CORRECTION
y = -2x^2 + 3
So, you must factor out.
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Or, complete the square.
Show me how to complete the square?
@lalaly lol she's perfect :D
Here it'd be very difficult :/
;-;
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