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Mathematics 15 Online
OpenStudy (anonymous):

x = 1/2 (y - 1)^2 + 8 Name the vertex.

OpenStudy (anonymous):

So (-1,8)?

Parth (parthkohli):

\( \color{Black}{\Rightarrow x = a(x - h)^2 + k }\) (h,k) is the vertex :)

Parth (parthkohli):

I didn't say -h,k

Parth (parthkohli):

1 will be positive in the vertex. \((1,8)\)

OpenStudy (anonymous):

What about for an equation like -2x^2 + 3?

Parth (parthkohli):

@lalaly :)

Parth (parthkohli):

I didn't understand the equation...there isn't an equals sign :/

Parth (parthkohli):

\( \color{Black}{\Rightarrow x = a(y - h)^2 + k }\) *CORRECTION

OpenStudy (anonymous):

y = -2x^2 + 3

Parth (parthkohli):

So, you must factor out.

Parth (parthkohli):

Or, complete the square.

OpenStudy (anonymous):

Show me how to complete the square?

Parth (parthkohli):

@lalaly lol she's perfect :D

Parth (parthkohli):

Here it'd be very difficult :/

OpenStudy (anonymous):

;-;

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