A body is thrown from ground vertically upwards into an empty tank of height H in minimum timeThe tank is now filled with water so that the acceleration inside is reduced to g/2 the height h from which the body should be thrown so that the time is unchanged is?
Not sure I understand the wording of the question. Could you clarify?
@CliffSedge sorry for the mistake in the question plz read it now
filling water will impose a considerable amount of buoyant force .. the value of g becoming g/2 refers only to that particle.. it means it has already calculated the net force acting down on the particle considering buoyant and gravitational forces..........i guess =P
Assuming this is basic kinematics, you can solve for h given the new acceleration. \[h=vt+1/2at^2\]
^that'd do it =)
"thrown upward into a tank" still sounds weird to me.
I bet your problem is this |dw:1338820797436:dw|
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