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Mathematics 9 Online
OpenStudy (anonymous):

The diagram below shows the map of a mine. How deep is the mine shaft?

OpenStudy (anonymous):

OpenStudy (anonymous):

I know this uses tangent, but I'm not sure whether it's

OpenStudy (anonymous):

or 6 tan 20˚

OpenStudy (unklerhaukus):

\[\tan\theta=\frac{\text{opposite}}{\text{adjacent}}\] \[\tan 20°=\frac?6\]

OpenStudy (anonymous):

I'm still not sure what it would be. How do you figure it out?

OpenStudy (unklerhaukus):

to isolate or solve for ? multiply both sides of the equation by 6

OpenStudy (unklerhaukus):

\[6\times \tan20°=6\times\frac?6\] \(\cdots=\cdots\)

OpenStudy (anonymous):

So would it be

OpenStudy (anonymous):

I'm new to this stuff, so I'm still confused.

OpenStudy (unklerhaukus):

Use this\[a\times\frac ba=\frac{ab}{a}=\frac{\cancel ab}{\cancel a}=\frac b1=b\]

OpenStudy (unklerhaukus):

a factor in the numerator and in the denominator may be canceled from the fraction

OpenStudy (anonymous):

How do you know whether to use a fraction or not?

OpenStudy (unklerhaukus):

a trigonometric function of an angle is always a fraction or ratio of two side-lengths

OpenStudy (unklerhaukus):

can you cancel the 6's on the right hand side?

OpenStudy (anonymous):

Yes.

OpenStudy (unklerhaukus):

and can you simplify the LHS, just remove an implied symbol

OpenStudy (anonymous):

6 tan 20˚?

OpenStudy (unklerhaukus):

that is it! \[?=6\tan20°\]

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