HELP: Find Special Functions and Graph.

1. g(x) = -/x/ then it gives you a an x/y table where "x" = (3,2,1,0,-1,-2,-3). Solve for "y" for each given "special function" then graph points.

Question

HELP:  Find Special Functions and Graph.    

1.  g(x) = -/x/    then it gives you a an x/y table where "x" = (3,2,1,0,-1,-2,-3).  Solve for "y" for each given "special function" then graph points.

experimentx · Answer

y = -|x| ??

anonymous · Answer

yes

anonymous · Answer

then the values for x on the x/y table are (3,2,1,0,-1,-2,-3)  so we have to figure for y.  The problem actually looks like this f(x) = /x/

experimentx · Answer

yes it is ..

experimentx · Answer

y = -|x|
y  = (-3,-2,-1,0,-1,-2,-3)

anonymous · Answer

Let see if I understand.  Since the (-) sign is before the special function then they all end up being a negative # instead of a positive one?

experimentx · Answer

yes ...
|some value | is always positive

anonymous · Answer

Ok.  I understand that one now.  I know that on the graph they are never a straight line.  Special functions are V shape and have a vertex.   I'm stuck now on the next problem because I keep getting a straight line.  g(x) = /x/+3  Same given X values of (3,2,1,0,-1,-2,-3)