Find the range: a) f(x) = ln(x+6) b) f(x) = 2/(3x-1) Please show steps so I can learn, I have the answers already. Thanks in advance
A) the range is all real numbers. If you understand how the ln graph works. For values 0-1, the range is negative. And for values above 1 are all positive and they increase/decrease exponentially. B) The range is all real numbers except for value 0. Seeing that there is (3x-1) in the denominator, this shows that there is a vertical asymptote, the lines will stretch to infinity for y-values. This range is all real numbers. Why except 0? because there is a horizontal asymptote of y=0. since 2/(3x-1) cannot be 0. For the denominator cannot be 0, or else it will be undefined. and since 2 not equals to 0, 2/(3x-1) cannot be equal to 0.
Great, thanks for your help, I appreciate it.
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