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Solve \[\log(5x+14)=0\]
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do you have an idea what the base of log(5x+ 14) is?
log(5x+14)=0 log(5x+14)=log_10^1 5x+14=1 5x=-13 x=-13/5
no..not reallyy :/
whenever a base is not given it is automatically assumed that the base is 10
how can you turn 0 into log1??
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0 = log_(10)1
so if you turn that into exponential function you'll get 10^0 = 5x + 14 anything raised to 0 is 1 so it becomes 1 = 5x + 14
ok, i see now, thanks people :D
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