SOlve 13^4x = 7 for x. I got like a random negative decimal... what am i doing wrong?
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OpenStudy (unklerhaukus):
\[13^{4x}=7\]
is this your question/
OpenStudy (unklerhaukus):
or \(13^4x=7\)
OpenStudy (anonymous):
the first one...
OpenStudy (unklerhaukus):
what answer did you get/
OpenStudy (anonymous):
i got -3.241345587040701
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OpenStudy (anonymous):
Take the natural log of both sides:
13^4x = 7
ln13^4x = ln7
by the properties of logarithms, we can pull down the exponent 4x:
4x(ln13) = ln7
4x = ln7/ln13
x = 4(ln7/ln13)
OpenStudy (anonymous):
the answer should be about 3.03....
OpenStudy (unklerhaukus):
your method is good @Hermeezey
but in you last step you made a little mistake
\[4x = \frac{\ln7}{\ln13}\]
\[x=\frac{\ln7}{4\ln13}\approx3.03\]
OpenStudy (unklerhaukus):
i mean \(x\approx0.1897\)
OpenStudy (anonymous):
oh yea sorry, i get confused when i'm typing
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OpenStudy (anonymous):
thanks :)
OpenStudy (unklerhaukus):
it is always good to check the solution by pluggin it into the original equation
\[13^{4\times0.1897}\approx13^{3/4}\approx6.8\approx7\]