can someone teach me a simple way, VERY VERY SIMPLE WAY to factor trinomials?
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OpenStudy (anonymous):
Quadratic trinomials?
OpenStudy (anonymous):
well im not sure just a trinomial like 9y^2-12yz-4z^2, i know how to solve them by just multiplying different numbers together, but what is the trinomials become greater numbers like 30 and 40?
OpenStudy (anonymous):
actually, could you explain how to factor this problem?: 9a^2+4bc-4c^2-b^2
OpenStudy (anonymous):
This one has a specific way
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
its tough..but you can make out that it is of the form 9a^2 - (b^2 -4bc+4c^2)
cant you?
OpenStudy (anonymous):
o yes! thanks!!!!!!
OpenStudy (anonymous):
now
the second part..look at it...if you can make it a perfect square..you can use the formula for differnce of squares cant u?
OpenStudy (anonymous):
x^2-y^2=(x+y)(x-y)?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
can you make the second term perfect square?
OpenStudy (anonymous):
i think so
OpenStudy (anonymous):
it is (b-2c)^2
OpenStudy (anonymous):
can u listen to me? instead of being impatient
OpenStudy (anonymous):
i am
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OpenStudy (anonymous):
so the second term is (b-2c)^2
so uve got
a^2 - (b-2c)^2
can u factor that out?
OpenStudy (anonymous):
it would be (a-b-2c)(a-b+2c)
OpenStudy (anonymous):
a+b-2c
OpenStudy (anonymous):
how?
OpenStudy (anonymous):
the first trm is a+b-2c
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