What is the vertex for the graph of y = 3x2 - 12x + 9? a.(-2, 21) b.(-2, 45) c.(2, -3) d.(2, -9)
Do you know about the shortcut ?
-b/2a
no i didnt know
Use -b/2a to find the x-vertex.
i mean the x-cordinate of vertex.
i do not know how...
ax^2 + bx + c If you compare, a = 3, b = 12, c = 9 \[-\frac{b}{2a} \to - \frac{12}{2(3)} \to -\frac{12}{6} \to -2\]
ok now what ?
that is the x cordinate. now insert that value in the equation to get the value of y.
i guess it will be easier after differentiation.. to understand, i mean
im so confused
u know about differentiation? @Andrewww ?
no i do not(:
oh, then.. saifoo's process is best for u, i guess ^^
bleeehhh i dont get it.
hey, have you come accross the quadratic equation and \[ax^2+bx+c=0\]
this helps you to know what a,b and c are, thats what the rest of the people have been talking about so far
so in your equation \[3x^2-12x+9=0\] a=3 b=-12 c=9 are you with me so far?
get back to me when you are ready
sorry lol i was eating and im back
so the answer is \[\frac{-b}{2a} \rightarrow \frac{-(-12)}{2 \times 3} \rightarrow \frac{12}{6} = 2\]
okay
its just a case of knowing where to get a,b and c and put those values in the formula to give you the answer. Later you will learn exactly why it works, but for now just do the plugging in.
now you have the value for x can you find the value for y
thankkkkkkks your much more help<3
\[3x^2-12x+9 \rightarrow 3(2)^2-12(2)+9 = 12-24+9 =-3\] the final answer is then (2,-3) which is answer C
YOUR A MATH GOD!(:
Nope, there are much better people here, just glad to help. :D
way to take a compliment<3
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