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Find the distance between these points. C(0, 4), T(-6, -3)
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Do you know the Distance formula?
x1+x2 over 2 and y1+y2 over 2?
Nope Distance between two points (x1,y1) & (x2,y2) is \[\Large D= \sqrt{(x2-x1)^2+(y2-y1)^2}\]
oh....
So what do you get?
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So would it be, (0-6)2 + (4-3)2?
(0, 4 ) (-6 ,-3) \[\sqrt{(-6-0)^2 + (-3-4)^2}\]
so would I multiply -6 twice? this is where I get lost
(-6)^2 = -6 x -6
so it'd be -6 as the outcome? and 49
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No what is -6 x -6 ?
36. so it would be 36+49? I did -3-4=-7, -7x-7=49
Yes But DON'T Forget the square root :D
Thanks for the help!
No problem :D
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