Question

3sinx=1+cos2x

Answer 1

if i get 16 kills and 6 deaths what is my kd :O

Answer 2

16:6, so 8:3?

Answer 3

\[\cos 2x= 1- 2\sin^2x \]
so \[3sinx= 1 + 1 - 2\sin^2 x\]

Answer 4

okay, from where would I go with that?

Answer 5

\[2\sin^2x+3sinx-2=0\]
Then let sinx be u
so that you have \[2u^2+3u-2=0\]
can you go on from there?

Answer 6

would I factor it so it ends up becoming (2u-1)(u+2)=0 and then set u back equal to sin^2x? or just sinx?

Answer 7

well u=sin x so you would set it back to sin x. But yes, the factoring part is right.

Answer 8

okay so I would get sinx=1/2 and -2?
thus, pi/6?

Answer 9

Yes.

Answer 10

alright, thank you!

Answer 11

np