Hello, im new to this and am a yr 9 highschool student, at the moment we are studying Linear equations in algebra and im completely confused Here are some examples of problems i dont understand: Make the letter indicated in brackets the subject of the formula: 3t2(to the power of 2) -q= 12. I really dont get it, if someone were to answer this question i would be really greatful and ask more questions ;) !!!
are there any preceding statements?
Not really, no.
hmm it says to make the letter in the bracekts the subject of the formula...does it look like this \[ [3t^2]^2 - q = 12\] exactly like that?? i mean there are brackets surrounding \(3t^2\)
I wrote to the power of two because i didnt know how to type it, i just meant 3t2-q= 12 but with the 2 being the power, if that makes sense ;) !
no no...the sense of my question was if there were brackets surrounding 3t^2 because the question says make the VARIABLE IN THE BRACKET the subject of formula...you getting my logic?
My bad, the (q) was the letter in the brackets e.g. 3t2-q=12 Then it said "Make the letter indicated in brackets the subject of the formula, which is (q). -_-
therefore we make q the subject of the formula
Precisely.
first get rid of \(3t^2\) how do you think that will be possible??
No clue.... possibly though cancel out???
Im guessing you put the q first as the subject for example: q=
yes you are right
to do that..we need to make 3t^2 be zero
Ok, how?
(3t^2)^2 - q ^what is the operation there?
i mean between (3t^2)^2 and q..what is the operation??
3t^2-q=12 was the sum....
Then make (q) the subject...
After that i didnt really get it..
just focus on (3t^2)^2 - q...what is the operation? addition? subtraction? multiplication? division? others?
DUDE DUDE DUDE the sum wasnt (3t^2)^2-q it was 3t^2-q=12 then make (q) the subject...
oh woops...
I dont think i was very clear, sorry...
okay then... 3t^2 - q = 12..what is the operation?
- ??
what is the operation in 3t^2 - q is it addition? subtraction? multiplication? division? others?
subtraction.... ?
good! and what is the opposite of subtraction?
addition?
yes yes!! now i want you to look at this...you know that you need to make it "q =" right? let's say you have 2 - q = 1 how do you get rid of 2?
q=2-1.... cancel out??? Dont really know....
that's right actually...but just focus on 2- q...how do you get rid of 2?
how can you make 2- q become 0 - q?
Can you go q-2 then subtract resulting in no 2????
do you mean 2 - q - 2?
No, just q - 2....
hmm no... how man you make 2 become 0?
how can*
I dont know... Explain?
1 - 1 = 0 2- 2 = 0 3 - 3 = 0 remember?
Ok, so to get 2-q you go 2-2= 0-q, so does that mean q is 2...
no no..you're not looking for q...you were just finding a way to make 2 become 0
look at 3t^2 - q how can you make 3t^2 0?
2-2=0
yes that's how you make 2 become 0..how do you make 3t^2 zero then?
Ummmmm..... ????
No clue...
This is what i didnt really understand..
you make 2 become 0 by subtracting 2 you make 1 become 0 by subtracting 1
So i make 3t^2 become 0 by???
think about it... 1- 1 = 0 2 - 2 = 0 x - x = 0 3t - 3t = 0
3t^2-3t^2= 0!!!
YES!!!
now 3t^2 - q - 3t^2 = 12 BUT since you subtract 3t^2 from the left side..you also subtract 3t^2 to the right side for it to be equal make sense?
therefore -q = 12 - 3t^2 you get that??
I THINK SO!!!!
now you need q = you have -q so you multiply everything by -1 to make q positive..make sense? q = -12 + 3t^2
YEAH, I THINK SO, IT SOUNDS LIKE SOMETHING MY TEACHER WAS SAYING!!!
so, QUICK RE-CAP...
3t^2 - q = 12 3t^2 - q - 3t^2 = 12 - 3t^2 -q = 12 - 3t^2 q = -12 + 3t^2
3T^2-Q=12 = 3T^2-Q-3T^2=12 = -Q=12-3T^2 = Q=-12 + 3T^2
yes
Soz, my internet dropped out, it does that here... you live in australia?
no
Where is Malin anyways?
Well, thanks for helping me with that sum...
Bye, if its ok i may talk to you tommorrow about more sums!
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