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Mathematics 9 Online
OpenStudy (anonymous):

Factorise

OpenStudy (anonymous):

\[2a ^{4}+a ^{2}b ^{2}+ab ^{3}+b ^{4}\] show steps

OpenStudy (anonymous):

@ParthKohli @lgbasallote @FoolForMath @dpaInc @.Sam. @Mertsj @jim_thompson5910 @Mertsj @myininaya

OpenStudy (anonymous):

Is it too Hard its like my last question dpalnc helped in last q so please atleast anyone help me please

OpenStudy (anonymous):

tough one... i don't think it's factorable...

OpenStudy (anonymous):

it is too long IIT enterance q

OpenStudy (anonymous):

just checked... it is factorable...

sam (.sam.):

\[a^2 \left(2a^2 +ab^3+b^2\right)+b^4\] \[a^2 \left(a \left(2 a+b^3\right)+b^2\right)+b^4\]

OpenStudy (experimentx):

lol ... i wouldn't do that without wolfram.

OpenStudy (anonymous):

it's the product of trinomials...

OpenStudy (anonymous):

nothing is going to happen using wolfram I used it already

OpenStudy (anonymous):

that's where i got the two trinomials from...

OpenStudy (anonymous):

which

OpenStudy (experimentx):

let's try it without wolfram ...

OpenStudy (experimentx):

(2a^2 + k)(a^2 + l) = ...

OpenStudy (anonymous):

the factorization to your problem...

OpenStudy (anonymous):

I'm fascinated that this has a factorization... It totally isn't obvious.

OpenStudy (anonymous):

I am closing this question opening another

OpenStudy (anonymous):

another is same like this try to solve

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