Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

How do i differentiate x^2 sec^2 3x

OpenStudy (anonymous):

We will want to use the product rule and the chain rule here.\[ \mathbf{Product\ Rule:}(fg)'=fg'+gf'\\ \mathbf{Chain\ Rule:}(f\circ g)'=(f'\circ g)g' \]

OpenStudy (anonymous):

product rule 2x(sec^23x)+x^2(2sec3x)(sex3x.tan3x.3)

OpenStudy (anonymous):

GOT IT! thanks :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!