The perimeter of a square exceeds that of another by 100cm and the area of the larger square exceeds three times the area of the smaller square by 325 cm^2. Find the length of a side of each of the squares .. Help is much appreciated :)

Question

anonymous · Answer

4x = 4y + 100
x^2 = 3y^2 + 325

solve these system of equations.... x being the side of the bigger square.

anonymous · Answer

simplify that first equation to x=y+25 and substitute into the second equation....

anonymous · Answer

It's still confusing me :X Sorry Bad in maths

anonymous · Answer

ok... substituting x=y+25 into the second equation, it becomes

(y+25)^2 = 3y^2 + 325

y^2 + 50y + 625 = 3y^2 + 325
-2y^2 + 50y - 300 = 0
2y^2 - 50y + 300 = 0
y^2 - 25y + 150 = 0
(y - 30)(y + 5) = 0  ===> y = 30

can you take it from here?

anonymous · Answer

Yes thank you :)