Question

f(x)=-1/3x^2
vertex=?
line of symmetry=?

Answer 1

written in the form f(x)=ax^2 + bx + c
your vertex will have x coordinate of -b/(2a)

Answer 2

still need help?

Answer 3

:) yes

Answer 4

can you identify in your function what a = , b = , c = ?

Answer 5

no I thought I was looking for x

Answer 6

you are looking for the vertex and the axis of symmetry... both require x. but the x coordinate of the vertex is obtained from -b/(2a). so if you know what a, b are, you can find the x coordinate of your vertex.