Could Someone explain how to do complex fractions?? PLEASEPLEASEPLEASE!!!!!

Question

anonymous · Answer

rewrite as multiplication by the reciprocal. i.e. numerator fraction times reciprocal of denominator fraction.

anonymous · Answer

um what?? the type of problem im talking about is like 1/x-2/x^2-3/x^3 over x-9/x

anonymous · Answer

e.g. $$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b}*\frac{d}{c}$$

anonymous · Answer

er,.. I might need more libral use of parentheses to know exactly what that means.  :">

anonymous · Answer

This is what I'm guessing that to be: $$\frac{\frac{1}{x}-\frac{2}{x^2}-\frac{3}{x^3}}{x-\frac{9}{x}}$$
Is that what you are trying to simplify?

anonymous · Answer

honestly hannahbananna this will give the best explanation of what you need to know and you can print it for reference. http://www.purplemath.com/modules/compfrac.htm

anonymous · Answer

If so, same as I said before, but you need to completely simplify the numerator and denominator separately into a single fraction each.

anonymous · Answer

Yeah, purplemath.com is a pretty good site.  :-)

anonymous · Answer

Alrighty~