Question

What are the x– and y–intercepts of the quadratic equation y = x2 + 2x – 3?

Answer 1

Set y=0 and solve for x to find x-intercept and set x=0 to find y-intercept

Answer 2

So, 0=x^2+2x-3
0=(x-1)(x+3)
Either x=1 or x=-1

y=-3

Answer 3

For the y-intercept, plug in 0 for x.
Y-Intercept = -3
Then, plug in 0 for y and solve the quadratic equation.
0 = x^2 + 2x - 3
0 = (x + 3)(x - 1)
x + 3 = 0
x = -3
x - 1 = 0
x = 1
Therefore, the x-intercepts are -3 and 1.