Question

Solve log (small 2)9 + log (small 2)a=log(small 2)13

Answer 1

\[\log_2 9 + \log_2 a = \log_2 13\] by product law... \[\log_2 9a = \log_2 13\] now i put it in exponential form \[2^{\log_2 13} = 9a\] now according to Logarithmic Property \(a^{\log_a b} = b\) this becomes

13 = 9a

a = 13/9

Answer 2

Thank you (:

Answer 3

@XxAdamZxX dont forget to give a medal (by pressing best answer) to the people who gave you the answer that satisfied you the most ;) it's a sign of appreciation and respect ehre

Answer 4

I'm so sorry! I didn't know :P