6(p^2-1)=5p
6p^2 - 6 =5p
6p^2 -5p -6=0
So I'm using the quad form.
5 +/- sqroot 25-4*6*-6

so 5 +/- sqroot 25-14 divided by 12 is this correct? If so where do I go from there?

Question

6(p^2-1)=5p
6p^2 - 6 =5p
6p^2 -5p -6=0
So I'm using the quad form. 
5 +/- sqroot 25-4*6*-6

so 5 +/- sqroot 25-14 divided by 12 is this correct? If so where do I go from there?

parthkohli · Answer

You should try the quadratic formula here :)

lgbasallote · Answer

rewrite as 6p^2 - 3p - 2p - 6 = 0

lgbasallote · Answer

^it's easier to factor that

lgbasallote · Answer

rather than bloodily doing trial and error

parthkohli · Answer

$ \color{Black}{\Rightarrow x = \Large{-b \pm \sqrt{b^2 - 4ac} \over 2a} }$

If you ever have probs factoring, try the quadratic formula.

anonymous · Answer

Is anyone there?