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Mathematics 19 Online
OpenStudy (anonymous):

Exact value.

OpenStudy (anonymous):

\[\sqrt{108\over15}\]

OpenStudy (btaylor):

108 factors to: 2 x 2 x 3 x 3 x 3 15 factors to: 3 x 5 You can eliminate one 3, since it cancels out. Then a 2 and a 3 come out of the radical, because they appear twice. You get \[2 \times 3 \sqrt{5} = 6\sqrt{5}\]

OpenStudy (anonymous):

so is it 18 root 5 over 5

OpenStudy (btaylor):

no, just 6 sqrt(5)

OpenStudy (anonymous):

ohhhhh. thank you!

OpenStudy (btaylor):

wait...6 sqrt(1/5) because the extra 5 was in the denominator. My bad!

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