Question

pleeeeeeeease help. :)

Answer 1

\[3q^8\over \sqrt{q^19}\]

Answer 2

\[\frac{3q^8}{\sqrt{q ^{^{19}}}}\]

Answer 3

Is that the problem?

Answer 4

it is 3q^8 over root q^19

Answer 5

\[\frac{3q^8}{\sqrt{q ^{18}q}}=\frac{3q^8}{q^9\sqrt{q}}\times\frac{\sqrt{q}}{\sqrt{q}}=\frac{3q^8\sqrt{q}}{q ^{10}}=\frac{3\sqrt{q}}{q^2}\]