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differential equations solve (1+2x2)y’=x√(1+2x2)+8xy x2 is square of x
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I believe this can be solved with an integrating factor
play around with it for a sec and you get: y'- (8x/1+2x2) y = x/sqrt(1+2x2)
which is the standard form for the integrating factor technique
wow they make that so confusing haha
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basically your integrating fator is e^intP(x) dx
you multiply that through your equation
you take the integral of both sides
the left side just becomes your integrating factor times y
the right side you have to take an integral
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solve for y and you end up with a general solution in terms of x and a constant
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