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A punter kicks a football upward with an initial speed of 48 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed.
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\[Vi=48m/s\]\[g=9.81m/s \]g=downward soo you h=\[48m/s \div9.81m/s=4.892...\]
now you need to rearrange ten formula for t is that formula saying\[h=rt-16t^2\]?
@LRGAUS95 ?
yes it is
@timo86m do u kno this
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h = rt − 16t2 0= rt − 16t2
3 seconds ooh r is 48
so the answer is 3 seconds
@ConradBarczyk you dont have to do 9.8 m/s^2 the formula is done for you :)
Yes 3 seconds
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LOL XD good point lol i did find the rest of the hard way :P \[t=\sqrt{h \div -16 +r}\]
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