can someone please show all the steps to find the difference: I am totally lost (-5x^2 + 2x – 5) – (7x^2 – 2x – 3)
Distribute the - sign to all terms on the right parenthesis and then add like terms
first rewrite without parentheses. don't touch anything in the first parentheses, just rewrite the terms \[-5x^2+2x-5\]
for the second one, distribute the minus sign, i.e. remover the parentheses and change all the signs \[– (7x^2 – 2x – 3) =-7x^2+2x+3\]
\[-5x^2-7x^2 +2x+ 2x -5 +3\] Quite sure you can go on from there. I just put the like terms together for you
this give \[(-5x^2 + 2x – 5) – (7x^2 – 2x – 3) \] \[=-5x^2 + 2x – 5– 7x^2 +2x + 3 \]
don't skip steps or try to do this in your head. write it out on paper now combine like terms
^^ and just practise, practice makes perfect.
so the final answer would be 5x^2 + 2x - 5- 7x^2 + 2x + 3
frustration, frustration frustration
You would have to add: \[-5x^2-7x^2\] \[2x+2x\] \[-5+3\] Hint: \[2x+2x = 4x\]
would that not be 4x^2 ? ?
\[2x + 2x \] ?
ok i c just the 4x
\[2x+2x=4x \]\[2x \times 2x = 4x^2\]
ok you are right thanks
So now just add the other terms together and let me know what you get...That should be your answer.
ok
Join our real-time social learning platform and learn together with your friends!