3x^2-7x-5=0 solutions? and x-intercepts?
solution -> solve for x x-int _> just same
use quadratic formula
You kinda have to use the quadratic formula. \[-b ±\sqrt{b ^{2} - 4ac}\over2a\]
I know I have to use the quadratic formula........the problem is using the formula
What do you mean?
I am not sure how?
a = 3 b =-7 and c = -5 You will get a complex answer.
a = 3 b = -7 c = -5 Just plug in numbers. The form for a quadratic is ax^2 + bx + c That's where it comes in.
ok
Do you understand?
Im not sure how to calc x
Your x will equal the complex number you get when you solve the quadratic equation..that is the x you are solving for.... x = quadratic equation.
\[1/6(7-\sqrt{109},1/6(7+\sqrt{109}\]
??
the x-intrecepts how do I write those?
a = 3 b = -7 c = -5 (7 ±√109)/6 You can approximate it if you want, but these are the solutions. Last line.
ordered pair for x-intr (-1,2)?
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