If y=xlog(x/(a+bx), show that d2y/dx2 = 1/x * (a/ a + bx)^2 Please help I need the solution by today
ugh..this is gonna be long...
have you tried it yet?
Yes of course
and what did you get?
After differentiating twice, I got
(a+bx+ab/(a+bx)^2) + a/x(a+bx)
Umm man, it's kinda urgent.. Do u mind telling me how to go about it? Thanks!
Such a beast of a question. Check out these links first derivative http://www.wolframalpha.com/input/?i=xlog%28x%2F%28a%2Bbx%29 2nd derivative http://www.wolframalpha.com/input/?i=%28a%2B%28a%2Bb+x%29+log%28x%2F%28a%2Bb+x%29%29%29%2F%28a%2Bb+x%29&lk=1&a=ClashPrefs_*Math- in that second link it's got what you want. Theres probably a clever-er way of doing it tho
Whoa what was that Can you explain? Or tell me the clever-er way?
I am not sure of the clever-er way or if it exists but on those pages, scroll down till you see the derivative part then click show working.
then see if you can understand whats it is doing. messy question tho
Right...
haha yeah...
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