Question

Find the primitive of y=e^(2lnx).
I tried integrating like normal but it ends up being all weird. The answer's meant to be x^3/3 + c, but I don't know how to get there. Help plz! Thanks!

Answer 1

Are you sure that it's \(\large y=x^{2lnx}\) ?
http://www.wolframalpha.com/input/?i=integrate+x^%282lnx%29
seems like an error function..

Answer 2

Ah sorry! It was y=e^(2lnx)

Answer 3

y=x²

Answer 4

AH! Thank you!! I didn't think of that.