Question

the quadratic equation 3x^2+px+q=0 has roots 2 and -3. find

a) value of p and q
b) the range of the values of k such that 3x^2+px+q=-3k has no real roots

Answer 1

sum of the roots=-p/3
product of the roots=q/3
in order to have complex or imaginary roots...discriminant<0.....where discriminant=p^2-4*(3)(q+3k)

Answer 2

use this :
sum of roots =-b/a
product of roots =c/a

Answer 3

then?
huh... why i'm so stupid at this?

Answer 4

http://www.learningincontext.com/Algebra-Web/chapt11.htm
See for help^_^